Convolution of sequences - MathOverflow most recent 30 from http://mathoverflow.net2013-05-23T13:59:46Zhttp://mathoverflow.net/feeds/question/107980http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/107980/convolution-of-sequencesConvolution of sequencesB-B2012-09-24T14:16:33Z2012-09-24T17:51:25Z
<p>Let for given real sequences $(a_n)_{n \in \mathbb Z}, (b_n)_{n \in \mathbb Z}$,
$c_n:=\sum_{k\in \mathbb Z} a_k b_{n-k}$ for $n \in \mathbb Z$ be the convolution of sequences $(a_n)$, $(b_n)$. </p>
<p>For classical convolution if one of two functions is in $L^p$, the second in $L^q$, where $1\leq p,q <\infty$ then their convolution $f*g$ is in $L^r$, where $\frac{1}{r}=\frac{1}{p}+\frac{1}{q}-1$.
Is it some similar type theorem true for convolution of sequences?</p>
http://mathoverflow.net/questions/107980/convolution-of-sequences/107995#107995Answer by Gerald Edgar for Convolution of sequencesGerald Edgar2012-09-24T17:51:25Z2012-09-24T17:51:25Z<p>Yes. True not only for $\mathbb Z$ but for for abelian (more generally unimodular) locally compact group. (20.18) in Hewitt & Ross, <em>Abstract Harmonic Analysis</em>.</p>