The Gysin map for a singular hypersurface - MathOverflow most recent 30 from http://mathoverflow.net2013-06-19T06:38:07Zhttp://mathoverflow.net/feeds/question/104336http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/104336/the-gysin-map-for-a-singular-hypersurfaceThe Gysin map for a singular hypersurfaceAlex Gavrilov2012-08-09T10:05:26Z2012-08-09T10:05:26Z
<p>Let $X$ be a projective complex manifold and <code>$Y\subset X$</code> be an irreducible
hypersurface. If $Y$ is <em>smooth</em>, there is a well known Gysin sequence.
However, even if $Y$ is not smooth, a kind of Gysin map can still be devised. </p>
<p>Consider a desingularization $f:\widetilde{Y}\to Y$ and the inclusion
$i:Y\hookrightarrow X$. We have two maps </p>
<p><code>$H^i(Y,\mathbb{Q})\to H^i(\widetilde{Y},\mathbb{Q})\to H^{i+2}(X,\mathbb{Q});$</code></p>
<p>the first one is <code>$f^*$</code> and the second one is the Poincare dual to <code>$(i\circ f)^*$</code>
(essentially the Gysin map). I am convinced that the composition does not depend on
desingularization, though I do not know a rigorous proof of this. </p>
<p><em>QUESTION</em>: Is the sequence </p>
<p><code>$H^i(Y,\mathbb{Q})\to H^{i+2}(X,\mathbb{Q})\to H^{i+2}(X\setminus Y,\mathbb{Q})$</code></p>
<p>exact (as it is in the smooth case)?</p>
<p>All I know about it is a result of Deligne
[Theorie de Hodge III. Publ. Math. IHES 44 (1974) pp. 5–77.; Corollary 8.2.8]
that </p>
<p><code>$H^i(\widetilde{Y},\mathbb{Q})\to H^{i+2}(X,\mathbb{Q})\to H^{i+2}(X\setminus Y,\mathbb{Q})$</code></p>
<p>is exact, but this is much weaker than what I need.</p>