Analogon to Brauer characters, if K not algebraically closed - MathOverflow most recent 30 from http://mathoverflow.net2013-06-20T09:59:12Zhttp://mathoverflow.net/feeds/question/103459http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/103459/analogon-to-brauer-characters-if-k-not-algebraically-closedAnalogon to Brauer characters, if K not algebraically closedBill2012-07-29T17:29:52Z2012-07-29T18:02:35Z
<p>Hello,
is there a theory for characters of a finite group over a field $K$ with prime characteristic, if $K$ is not algebraically closed? For algebraically closed fields $K$ for example Brauer found some interesting theorems.</p>
<p>Any hints and suggested literature is very welcome.</p>
<p>Regards, Bill</p>
http://mathoverflow.net/questions/103459/analogon-to-brauer-characters-if-k-not-algebraically-closed/103463#103463Answer by Florian Eisele for Analogon to Brauer characters, if K not algebraically closedFlorian Eisele2012-07-29T18:02:35Z2012-07-29T18:02:35Z<p>There really isn't any need for character theory over non-algebraically closed fields. The Grothendieck group of $KG$ embeds into the Grothendieck group of $\bar K G$ (i.e. of the group ring over the algebraic closure). Therefore all information about a $KG$-module $M$ you could possibly hope to recover from any type of "character of $M$" is already contained in the Brauer character of the $\bar K G$-module $\bar K \otimes M$. </p>
<p>Also, the values of the Brauer character of $M$ will lie in the ring of Witt-vectors over $K$. </p>