Actions on Sⁿ with quotient Sⁿ - MathOverflow most recent 30 from http://mathoverflow.net2013-05-22T14:35:40Zhttp://mathoverflow.net/feeds/question/103098http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/103098/actions-on-s-with-quotient-sActions on Sⁿ with quotient SⁿAnton Petrunin2012-07-25T12:41:25Z2012-07-29T13:40:24Z
<blockquote>
<p>What is known about isometric actions on $\mathbb S^n$ such that the quotient space is homeomorphic to $\mathbb S^n$?</p>
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<p><strong>Comments.</strong></p>
<ul>
<li>I am mostly interested in (maybe trivial) properties of such actions for large $n$. Say, it is true that any such action is generated by rotations around $\mathbb S^{n-2}$'s; what else?</li>
<li>I see that the orientation preserving part of Coxeter's group has this property. </li>
<li>Now I see that there are other examples for $\mathbb S^3$, thanks to Lee Mosher. It seems that taking joints you get such examples in higher dimensions.</li>
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http://mathoverflow.net/questions/103098/actions-on-s-with-quotient-s/103103#103103Answer by Lee Mosher for Actions on Sⁿ with quotient SⁿLee Mosher2012-07-25T13:19:36Z2012-07-25T13:37:08Z<p>Your question translates into the language of orbifolds as saying: what is known about spherical $n$-orbifolds with underlying space homeomorphic to $S^n$? </p>
<p>In $S^2$, the examples you give are all there are. </p>
<p>Orbifolds with the geometry of $S^3$ were enumerated by William Dunbar in his thesis. His published paper MR1118824 contains the enumeration of the 21 oriented $S^3$-orbifolds which do not have a circle fibration over a 2-orbifold. The equivalence relation here is up to orientation preserving isometry; if you allow orientation reversing isometry then the list is cut down somewhat. Each of the 21 has underlying space homeomorphic to $S^3$. At the end of Dunbar's paper you will see that exactly 8 of the 21 are orientable double covers of Coxeter group quotients, with the corresponding Dynkin diagrams listed out explicitly. That leaves 13 examples as you ask for in $S^3$. </p>
http://mathoverflow.net/questions/103098/actions-on-s-with-quotient-s/103441#103441Answer by Dmitri for Actions on Sⁿ with quotient SⁿDmitri2012-07-29T10:52:00Z2012-07-29T13:40:24Z<p>In the following article of M.A.Mikhailova (М.А. Михайлова)</p>
<p>Изв. АН СССР. Сер. матем., 48:1 (1984)</p>
<p>О ФАКТОРПРОСТРАНСТВЕ ПО ДЕЙСТВИЮ КОНЕЧНОЙ ГРУППЫ, ПОРОЖДЕННОЙ ПСЕВДООТРАЖЕНИЯМИ.</p>
<p><a href="http://www.mathnet.ru/links/33220b8c84645bec685e85bf17d65994/im1420.pdf" rel="nofollow">http://www.mathnet.ru/links/33220b8c84645bec685e85bf17d65994/im1420.pdf</a></p>
<p>it is proven:</p>
<p><strong>Theorem</strong>. <em>The quotient $\mathbb R^n/G$ by a linear action of a finite group $G$ is homeomorphic to $\mathbb R^n$ if and only if $G$ is generated by pseudo-reflections (i.e, rotations of $\mathbb R^n$ that fix a subspace of codimension 2).</em> </p>
<p>The proof relies on a complete classification of finite groups generated by pseudo-reflections (there is a reference to this classification at the end of the article)</p>
<p>(there should be of course an English translation of this article, but I can not find it now).</p>