Geometric Measure Theory On Euclidean Spaces - MathOverflow most recent 30 from http://mathoverflow.net2013-05-21T01:40:41Zhttp://mathoverflow.net/feeds/question/102887http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/102887/geometric-measure-theory-on-euclidean-spacesGeometric Measure Theory On Euclidean SpacesJeremy Young2012-07-22T18:11:02Z2012-07-23T07:51:27Z
<p>Dear all,</p>
<p>I have recently found the following discussion:
<a href="http://mathoverflow.net/questions/102061/hausdorff-measure-and-minkowskis-content-boundary-measures" rel="nofollow">http://mathoverflow.net/questions/102061/hausdorff-measure-and-minkowskis-content-boundary-measures</a>
regarding different boundary measures on $\mathbb{R}^n $ . </p>
<p>The discussion made me wondering:</p>
<p>Is there any example in the opposite direction?</p>
<p>i.e. an example of a set $A \subseteq \mathbb{R} ^n $ such that $ Leb^+ (A) > H^{n-1} (\partial A) $ ? </p>
<p>Thanks in advance ! </p>
http://mathoverflow.net/questions/102887/geometric-measure-theory-on-euclidean-spaces/102891#102891Answer by Tapio Rajala for Geometric Measure Theory On Euclidean SpacesTapio Rajala2012-07-22T19:22:04Z2012-07-22T19:22:04Z<p>Take $[0,1]\times \{0\} \subset \mathbb{R}^2$.</p>
http://mathoverflow.net/questions/102887/geometric-measure-theory-on-euclidean-spaces/102892#102892Answer by Anton Petrunin for Geometric Measure Theory On Euclidean SpacesAnton Petrunin2012-07-22T19:23:20Z2012-07-23T07:51:27Z<p>$A=\mathbb{Z}\subset \mathbb R^2$. In this case $\partial\mathbb{Z}= \mathbb{Z}$ and
$\mathop{Leb}^+(\mathbb Z)=\infty$ and $H^1(\mathbb Z)=0$.</p>
<p>You can get a bounded example of the same type.
Take a countable nowhere dense set $A$ in the unit disc such that the $\varepsilon$-neighborhood of $A$ contains a disc of radius $\sqrt[3]{\varepsilon}$.</p>