What is the isometry group of $AD(V)$? - MathOverflow most recent 30 from http://mathoverflow.net2013-05-25T22:08:43Zhttp://mathoverflow.net/feeds/question/102274http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/102274/what-is-the-isometry-group-of-advWhat is the isometry group of $AD(V)$?yanqing 2012-07-15T09:01:34Z2012-07-15T09:01:34Z
<p>Let $V$ be a compressionbody. </p>
<p>Annulus and disk complex $AD(V)$ is defined to be:</p>
<p>Vertex: An istopy class of spanning annulus or an essential disk. </p>
<p>Place an edge between two vertices if the two vertices are disjoint. </p>
<p>Obivously, $AD(V)$ is an 1-dimensional simplicial complex. </p>
<p>My question is :</p>
<p>What is the isometry group of $AD(V)$? </p>
<p>Note: I heard that S.Schleimer just proved the isometry group of disk complex is isometric to
the mapping class group of handlebody $V$. </p>