What is the isometry group of $AD(V)$? - MathOverflow most recent 30 from http://mathoverflow.net 2013-05-25T22:08:43Z http://mathoverflow.net/feeds/question/102274 http://www.creativecommons.org/licenses/by-nc/2.5/rdf http://mathoverflow.net/questions/102274/what-is-the-isometry-group-of-adv What is the isometry group of $AD(V)$? yanqing 2012-07-15T09:01:34Z 2012-07-15T09:01:34Z <p>Let $V$ be a compressionbody. </p> <p>Annulus and disk complex $AD(V)$ is defined to be:</p> <p>Vertex: An istopy class of spanning annulus or an essential disk. </p> <p>Place an edge between two vertices if the two vertices are disjoint. </p> <p>Obivously, $AD(V)$ is an 1-dimensional simplicial complex. </p> <p>My question is :</p> <p>What is the isometry group of $AD(V)$? </p> <p>Note: I heard that S.Schleimer just proved the isometry group of disk complex is isometric to the mapping class group of handlebody $V$. </p>