estimate of metric tensors in terms of curvatures - MathOverflow most recent 30 from http://mathoverflow.net2013-06-19T10:56:12Zhttp://mathoverflow.net/feeds/question/100988http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/100988/estimate-of-metric-tensors-in-terms-of-curvaturesestimate of metric tensors in terms of curvaturesBewSMA2012-06-30T06:11:58Z2012-06-30T09:49:19Z
<p>I would appreciate if someone knows how to get the following estimates:</p>
<p>Let $\rho_m$ is a sequence of real numbers approaching $\infty$. Consider a sequence of Riemannian metrics $g^{(m)}$ on $S^3$ such that they satisfy the following two assumptions:</p>
<ol>
<li>For all sectional curvatures of $(S^3, g^{(m)})$ we have $$1-A\rho_m^{-\frac{1}{4}}\leq K(g^{(m)})(x)\leq 1+A\rho_m^{-\frac{1}{4}}$$ for any $x\in S^3$ and $A$ is a positive constant independent of $m$. </li>
<li>The covariant derivatives of Riemann curvature tensors have uniform bounds, i.e., $$\sup_{S^3}|\nabla^lRm(g^{(m)})|_{g^{(m)}}\leq B(l),$$ where $l=0,1,2,\ldots$, and $B(l)$ does not depend on $m$.</li>
</ol>
<p>Want to show the following estimates: for a small positive constant $\delta>0$ we have
\begin{equation}
||g^{(m)}-g_0||_{C^l(S^3,g_0)}\leq C(l)\rho_m^{-\delta },
\end{equation}
where $g_0$ is the metric with constant sectional curvature one and $C(l)$, $l=0,1,2,\ldots$, are constants independent of $m$.</p>
<p>Any hint or reference will be really appreciated!</p>
http://mathoverflow.net/questions/100988/estimate-of-metric-tensors-in-terms-of-curvatures/100992#100992Answer by Anton Petrunin for estimate of metric tensors in terms of curvaturesAnton Petrunin2012-06-30T09:49:19Z2012-06-30T09:49:19Z<p>All your assumptions survive after arbitrary smooth reparametriztion of $\mathbb S^3$.
Therefore maximum you can expect is that for any $n$ there is a reparamtrization of $\mathbb S^3$ such that
\begin{equation}
||h^{(m)}-g_0||_{C^l(S^3,g_0)}\leq C(l)\rho_m^{-\delta },
\end{equation}
holds for the pullback $h^{(m)}$ of $g^{(m)}$. </p>
<p>This is indeed true, the exponential maps give such reparametrizations between balls of radius $r<\pi$ for all larde $n$.
It remains to glue two such balls in a neigborhood of the equator.
To do this choose a nice partition of unity $m_1, m_2$ for these balls,
rotate parametrizations so that they are almost identical near equator
and send a point to the baricenter of its images with the masses $m_1$ and $m_2$
(see How to Conjugate $C^1$-close group actions by Grove and Karcher).</p>
<p>It seems that $\delta=1/4$ will do, but for sure it works for any $\delta<1/4$.</p>