14
$\begingroup$

If $A$ is a commutative ring we have the estimate $$ \dim (A)+1 \le \dim (A[x])\le 2\dim (A)+1 $$ for the Krull dimension, with $\dim (A)+1 = \dim (A[x])$ for Noetherian rings. I am looking for nice examples of rings $A$ so that $A[x]$ has Krull dimension $\dim (A)+2, \dim(A)+3,\ldots ,2\dim(A)+1$.

$\endgroup$

1 Answer 1

8
$\begingroup$

Your question is essentially completely answered in the paper The dimension sequence of a commutative ring by Arnold and Gilmer (Amer. J. Math. 96 (1974), 385--408).

EDIT: The aforementioned paper by Arnold and Gilmer treats the case of an arbitrary finite number of variables. Since you are interested only in the case of one variable, the general but still rather concrete construction of rings with the desired properties given in Bourbaki's Algèbre commutative VIII.2 Exercice 7 should be sufficient.

$\endgroup$
1
  • $\begingroup$ I finally found the exercise in the original edition (the engish translation has only chapters I to VII). I tried to construct the rings explicitly, but was referred to several other exercises (basically all exercises before). If someone can give me some examples more easily, I am still grateful. $\endgroup$ May 22, 2013 at 14:12

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.